cross-posted from: https://lemmy.ml/post/39334581
this post was submitted on 22 Nov 2025
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I didn't mean that bash has no local variables, but rather that if you want to use a function as such without capturing stdout, you need variables that are scoped across your functions, which is usually global or at least effectively global.
Turns out you can, by using () instead of {} in the function declaration you can run the function in a subshell where changes to variables are scoped to the subshell and functions are local.
That doesn't help you if you want to get the result of something that happened in the function without capturing stdout, does it?