Did you ever saw a char and thought: "Damn, 1 byte for a single char is pretty darn inefficient"? No? Well I did. So what I decided to do instead is to pack 5 chars, convert each char to a 2 digit integer and then concat those 5 2 digit ints together into one big unsigned int and boom, I saved 5 chars using only 4 instead of 5 bytes. The reason this works is, because one unsigned int is a ten digit long number and so I can save one char using 2 digits. In theory you could save 32 different chars using this technique (the first two digits of an unsigned int are 42 and if you dont want to account for a possible 0 in the beginning you end up with 32 chars). If you would decide to use all 10 digits you could save exactly 3 chars. Why should anyone do that? Idk. Is it way to much work to be useful? Yes. Was it funny? Yes.

Anyone whos interested in the code: Heres how I did it in C: https://pastebin.com/hDeHijX6

Yes I know, the code is probably bad, but I do not care. It was just a funny useless idea I had.

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[–] ChaoticNeutralCzech@feddit.org 1 points 8 hours ago* (last edited 6 hours ago)

Oh, I didn't know that they were a LUT of jump addresses. Stil, a LUT of values would be more space-efficient and likely faster. Also, what if the values are big and sparse, e.g.

switch (banknoteValue) {
    case 5000:
        check_uv();
        check_holograph();
    case 2000:
        check_stripe();
    case 1000:
        check_watermark();
}

...does the compiler make it into an if-else-like machine code instead?