WFloyd

Thanks for the correction! I got way ahead of myself.

When wind speed doubles, the energy it carries increases eightfold,

Edit: I'm wrong, see edit below!

Huh? Kinetic energy increase is square, not cubic.

KE=1/2 m v^2

So every doubling of speed should increase the available kinetic energy by 4 times, not 8. 3 times the speed is 9 times the energy. Granted there are probably some efficiency gains in excess of this at the low end, ~~but as a rule that's just wrong.~~

Edit: Cool, I learned something new! I neglected to consider it in terms of power, just thought about kinetic energy.

So something like: KE = 1/2 m v^2

= 1/2 ( rho V) v^2

= 1/2 ( rho A d) (d/t)^2

= 1/2 rho A d^3 1/t^2

Where P = KE/t

Thus:

P = 1/2 rho A (d/t)^3

= 1/2 rho A v^3

Lots of other aspects I'm sure I have wrong, but I see how the cubic came to be.

Is that the breast you can do?